The problem asks to find the next time after 12:00 when the minute and hour hands of a clock overlap. The hint suggests using the concept of rotational motion.

Applied MathematicsClock ProblemRotational MotionAngular SpeedTime CalculationWord Problem
2025/7/27

1. Problem Description

The problem asks to find the next time after 12:00 when the minute and hour hands of a clock overlap. The hint suggests using the concept of rotational motion.

2. Solution Steps

Let the angular speed of the hour hand be ωh\omega_h and the angular speed of the minute hand be ωm\omega_m. We know that the minute hand completes a full rotation (2π2\pi radians) in 60 minutes, so
ωm=2π60=π30 rad/min \omega_m = \frac{2\pi}{60} = \frac{\pi}{30} \text{ rad/min}
The hour hand completes a full rotation (2π2\pi radians) in 12 hours (720 minutes), so
ωh=2π720=π360 rad/min \omega_h = \frac{2\pi}{720} = \frac{\pi}{360} \text{ rad/min}
Let tt be the time in minutes after 12:00 when the minute and hour hands overlap again.
The angle covered by the minute hand is θm=ωmt=π30t\theta_m = \omega_m t = \frac{\pi}{30} t.
The angle covered by the hour hand is θh=ωht=π360t\theta_h = \omega_h t = \frac{\pi}{360} t.
Since we are looking for the first time after 12:00 when they overlap, the difference in the angles covered by the minute and hour hands must be 2π2\pi radians (one full rotation). So,
θmθh=2π \theta_m - \theta_h = 2\pi
π30tπ360t=2π \frac{\pi}{30} t - \frac{\pi}{360} t = 2\pi
Divide both sides by π\pi:
t30t360=2 \frac{t}{30} - \frac{t}{360} = 2
Multiply both sides by 360:
12tt=720 12t - t = 720
11t=720 11t = 720
t=7201165.45 minutes t = \frac{720}{11} \approx 65.45 \text{ minutes}
The time is approximately 65.45 minutes after 12:
0

0. Convert the decimal part of the minutes to seconds:

0.45 minutes×60 seconds/minute27 seconds0.45 \text{ minutes} \times 60 \text{ seconds/minute} \approx 27 \text{ seconds}.
So, the time is approximately 1 hour, 5 minutes, and 27 seconds. More precisely,
t=72011 minutes=65511 minutes t = \frac{720}{11} \text{ minutes} = 65\frac{5}{11} \text{ minutes}
511 minutes=511×60 seconds=30011 seconds27.27 seconds \frac{5}{11} \text{ minutes} = \frac{5}{11} \times 60 \text{ seconds} = \frac{300}{11} \text{ seconds} \approx 27.27 \text{ seconds}
So the time when they meet is 1:05:27.27 approximately.

3. Final Answer

The time when the minute and hour hands overlap again is 72011\frac{720}{11} minutes after 12:00, which is approximately 1:05:
2

7. The time is $\frac{720}{11}$ minutes.

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