The problem asks to find the area of a shape, which could be a parallelogram, trapezoid, rhombus, or kite. The lengths of the diagonals are given as 7 cm and (6+9) cm = 15 cm. The problem specifies to round the answer to the nearest tenth, if necessary.

1. Problem Description

The problem asks to find the area of a shape, which could be a parallelogram, trapezoid, rhombus, or kite. The lengths of the diagonals are given as 7 cm and (6+9) cm = 15 cm. The problem specifies to round the answer to the nearest tenth, if necessary.

2. Solution Steps

Since the given figure displays two diagonals intersecting perpendicularly, and the question specifies rhombus or kite, we can assume the figure to be a rhombus or kite. The area of a rhombus or kite can be calculated using the lengths of its diagonals.

Area of a rhombus or kite = $\frac{1}{2} \times d_1 \times d_2$, where $d_1$ and $d_2$ are the lengths of the diagonals.

In this case, $d_1 = 7$ cm and $d_2 = 6 + 9 = 15$ cm.

Area = $\frac{1}{2} \times 7 \times 15 = \frac{105}{2} = 52.5$ cm$^2$

3. Final Answer

5

2. 5 cm$^2$