Given the equation $2 \log_y x = 3$, find the relationship between $x$ and $y$.

AlgebraLogarithmsExponentsEquation Solving
2025/4/5

1. Problem Description

Given the equation 2logyx=32 \log_y x = 3, find the relationship between xx and yy.

2. Solution Steps

We are given the equation 2logyx=32 \log_y x = 3.
First, divide both sides of the equation by 2:
logyx=32\log_y x = \frac{3}{2}
We can rewrite this logarithmic equation in exponential form. The general formula for converting a logarithm to an exponential is:
logba=c    bc=a\log_b a = c \implies b^c = a
Applying this to our equation logyx=32\log_y x = \frac{3}{2}, we get:
y32=xy^{\frac{3}{2}} = x
To eliminate the fractional exponent, we can raise both sides of the equation to the power of 2:
(y32)2=x2(y^{\frac{3}{2}})^2 = x^2
y3=x2y^3 = x^2

3. Final Answer

The relationship between xx and yy is y3=x2y^3 = x^2.

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