We are asked to evaluate the expression $A = 2025^3 - 2024 \cdot 2025^2 - 2024^2 \cdot 2025 + 2024^3$.

AlgebraPolynomialsFactoringAlgebraic ManipulationSimplification
2025/8/5

1. Problem Description

We are asked to evaluate the expression A=20253202420252202422025+20243A = 2025^3 - 2024 \cdot 2025^2 - 2024^2 \cdot 2025 + 2024^3.

2. Solution Steps

Let a=2025a = 2025 and b=2024b = 2024. Then the expression becomes:
A=a3ba2b2a+b3A = a^3 - b a^2 - b^2 a + b^3.
We can rewrite this as:
A=a3+b3ba2b2aA = a^3 + b^3 - b a^2 - b^2 a
A=(a3+b3)(ba2+b2a)A = (a^3 + b^3) - (b a^2 + b^2 a)
We can factor each term:
a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2)
ba2+b2a=ab(a+b)b a^2 + b^2 a = ab(a + b)
So, A=(a+b)(a2ab+b2)ab(a+b)A = (a+b)(a^2 - ab + b^2) - ab(a+b)
We can factor out (a+b)(a+b):
A=(a+b)(a2ab+b2ab)A = (a+b)(a^2 - ab + b^2 - ab)
A=(a+b)(a22ab+b2)A = (a+b)(a^2 - 2ab + b^2)
The term (a22ab+b2)(a^2 - 2ab + b^2) is a perfect square:
a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a-b)^2
So, A=(a+b)(ab)2A = (a+b)(a-b)^2
Now, we substitute a=2025a = 2025 and b=2024b = 2024:
A=(2025+2024)(20252024)2A = (2025 + 2024)(2025 - 2024)^2
A=(4049)(1)2A = (4049)(1)^2
A=40491A = 4049 \cdot 1
A=4049A = 4049

3. Final Answer

The final answer is 4049.

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