We need to factor the quadratic expressions given in problems 22, 23, 25, 26, 28, and 29.

AlgebraQuadratic EquationsFactorizationPerfect Square TrinomialDifference of Squares
2025/8/5

1. Problem Description

We need to factor the quadratic expressions given in problems 22, 23, 25, 26, 28, and
2
9.

2. Solution Steps

Problem 22: y2+2y+1y^2 + 2y + 1
This is a perfect square trinomial.
(a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2
In this case, a=ya=y and b=1b=1.
Therefore, y2+2y+1=(y+1)2=(y+1)(y+1)y^2 + 2y + 1 = (y+1)^2 = (y+1)(y+1).
Problem 23: y23y28y^2 - 3y - 28
We need to find two numbers that multiply to -28 and add to -

3. These numbers are -7 and

4. Therefore, $y^2 - 3y - 28 = (y-7)(y+4)$.

Problem 25: x28x240x^2 - 8x - 240
We need to find two numbers that multiply to -240 and add to -

8. These numbers are -20 and

1

2. Therefore, $x^2 - 8x - 240 = (x-20)(x+12)$.

Problem 26: x226x+165x^2 - 26x + 165
We need to find two numbers that multiply to 165 and add to -
2

6. These numbers are -11 and -

1

5. Therefore, $x^2 - 26x + 165 = (x-11)(x-15)$.

Problem 28: x249x^2 - 49
This is a difference of squares.
a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)
In this case, a=xa=x and b=7b=7.
Therefore, x249=(x7)(x+7)x^2 - 49 = (x-7)(x+7).
Problem 29: x29x^2 - 9
This is a difference of squares.
a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)
In this case, a=xa=x and b=3b=3.
Therefore, x29=(x3)(x+3)x^2 - 9 = (x-3)(x+3).

3. Final Answer

2

2. $(y+1)(y+1)$

2

3. $(y-7)(y+4)$

2

5. $(x-20)(x+12)$

2

6. $(x-11)(x-15)$

2

8. $(x-7)(x+7)$

2

9. $(x-3)(x+3)$

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