The problem asks for the interquartile range (IQR) of the given data set: 45, 40, 23, 34, 95, 57, 62, 48, 50, 44, 51, 47. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).

Probability and StatisticsInterquartile RangeIQRQuartilesDescriptive StatisticsData Analysis
2025/3/12

1. Problem Description

The problem asks for the interquartile range (IQR) of the given data set: 45, 40, 23, 34, 95, 57, 62, 48, 50, 44, 51,
4

7. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).

2. Solution Steps

First, we need to sort the data set in ascending order:
23, 34, 40, 44, 45, 47, 48, 50, 51, 57, 62, 95
Next, we find the median (Q2) of the data set. Since there are 12 data points, the median is the average of the 6th and 7th values:
Q2=(47+48)/2=47.5Q2 = (47 + 48) / 2 = 47.5
Now, we find the first quartile (Q1), which is the median of the lower half of the data (excluding the median if the number of data points is odd):
Lower half: 23, 34, 40, 44, 45, 47
Q1=(40+44)/2=42Q1 = (40 + 44) / 2 = 42
Then, we find the third quartile (Q3), which is the median of the upper half of the data:
Upper half: 48, 50, 51, 57, 62, 95
Q3=(51+57)/2=54Q3 = (51 + 57) / 2 = 54
Finally, we calculate the interquartile range (IQR):
IQR=Q3Q1=5442=12IQR = Q3 - Q1 = 54 - 42 = 12

3. Final Answer

B. 12

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