The problem asks to find the slope of the line that passes through the points in the given table. The table contains the following points: (3, 14), (7, 8), (9, 5), (15, -4).

AlgebraLinear EquationsSlopeCoordinate Geometry
2025/3/12

1. Problem Description

The problem asks to find the slope of the line that passes through the points in the given table. The table contains the following points: (3, 14), (7, 8), (9, 5), (15, -4).

2. Solution Steps

The slope of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Let's use the points (3, 14) and (7, 8) to calculate the slope.
x1=3x_1 = 3, y1=14y_1 = 14
x2=7x_2 = 7, y2=8y_2 = 8
m=81473=64=32m = \frac{8 - 14}{7 - 3} = \frac{-6}{4} = -\frac{3}{2}
Let's verify the slope using another pair of points: (9, 5) and (15, -4).
x1=9x_1 = 9, y1=5y_1 = 5
x2=15x_2 = 15, y2=4y_2 = -4
m=45159=96=32m = \frac{-4 - 5}{15 - 9} = \frac{-9}{6} = -\frac{3}{2}
The slope is 32-\frac{3}{2}.

3. Final Answer

-3/2

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