The problem requires us to graph two lines: $y = 3x - 5$ and $y = -4x + 9$. We need to find two points for each line.

1. Problem Description

The problem requires us to graph two lines: $y = 3x - 5$ and $y = -4x + 9$. We need to find two points for each line.

2. Solution Steps

For the line $y = 3x - 5$:

* Choose $x = 0$. Then $y = 3(0) - 5 = -5$. So, the point is $(0, -5)$.

* Choose $x = 1$. Then $y = 3(1) - 5 = 3 - 5 = -2$. So, the point is $(1, -2)$.

For the line $y = -4x + 9$:

* Choose $x = 0$. Then $y = -4(0) + 9 = 9$. So, the point is $(0, 9)$.

* Choose $x = 1$. Then $y = -4(1) + 9 = -4 + 9 = 5$. So, the point is $(1, 5)$.

3. Final Answer

The points for the line $y = 3x - 5$ are $(0, -5)$ and $(1, -2)$.

The points for the line $y = -4x + 9$ are $(0, 9)$ and $(1, 5)$.