We are given a right triangle with a hypotenuse of 8 cm and one leg of 4 cm. We need to find the length of the other leg, rounded to the nearest tenth.

1. Problem Description

We are given a right triangle with a hypotenuse of 8 cm and one leg of 4 cm. We need to find the length of the other leg, rounded to the nearest tenth.

2. Solution Steps

We can use the Pythagorean theorem to find the length of the missing leg. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse ($c$) is equal to the sum of the squares of the lengths of the other two legs ($a$ and $b$).

$a^2 + b^2 = c^2$

Let $a = 4$ cm and $c = 8$ cm. We need to find $b$.

$4^2 + b^2 = 8^2$

$16 + b^2 = 64$

$b^2 = 64 - 16$

$b^2 = 48$

$b = \sqrt{48}$

$b \approx 6.928$

Rounding to the nearest tenth, we get $b \approx 6.9$ cm.

3. Final Answer

6.9