We are given a right triangle with legs measuring 7 cm and 4 cm. We need to find the length of the hypotenuse and round to the nearest tenth.

1. Problem Description

We are given a right triangle with legs measuring 7 cm and 4 cm. We need to find the length of the hypotenuse and round to the nearest tenth.

2. Solution Steps

We can use the Pythagorean theorem to find the hypotenuse of the right triangle. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b).

$a^2 + b^2 = c^2$

In this case, $a = 7$ cm and $b = 4$ cm. So we have:

$7^2 + 4^2 = c^2$

$49 + 16 = c^2$

$65 = c^2$

$c = \sqrt{65}$

Now we need to find the square root of 65 and round to the nearest tenth.

$\sqrt{65} \approx 8.062257748$

Rounding to the nearest tenth, we get $8.1$.

3. Final Answer

8.1 cm