The problem asks us to solve a series of linear equations for the unknown variables. The equations are: 1. $3a - 7 = 26$
2025/4/8
1. Problem Description
The problem asks us to solve a series of linear equations for the unknown variables. The equations are:
1. $3a - 7 = 26$
2. $9f + 5 = 77$
3. $2k - 20 = 40$
4. $6b - 4 = 38$
5. $10h + 58 = -2$
6. $-4d + 17 = 65$
7. $8m + 11 = -53$
8. $5z - 1.75 = 8.25$
9. $\frac{1}{2}n + 40 = 55$
1
0. $-\frac{1}{4}c - 5 = 20$
1
1. $4.8g + 9 = 33$
1
2. $\frac{1}{3}p + 22 = 18$
1
3. $1.2y + 0.52 = 7$
1
4. $2.5t + 24 = 14$
1
5. $5j + \frac{2}{3} = -\frac{1}{6}$
2. Solution Steps
1. $3a - 7 = 26$
Add 7 to both sides:
Divide by 3:
2. $9f + 5 = 77$
Subtract 5 from both sides:
Divide by 9:
3. $2k - 20 = 40$
Add 20 to both sides:
Divide by 2:
4. $6b - 4 = 38$
Add 4 to both sides:
Divide by 6:
5. $10h + 58 = -2$
Subtract 58 from both sides:
Divide by 10:
6. $-4d + 17 = 65$
Subtract 17 from both sides:
Divide by -4:
7. $8m + 11 = -53$
Subtract 11 from both sides:
Divide by 8:
8. $5z - 1.75 = 8.25$
Add 1.75 to both sides:
Divide by 5:
9. $\frac{1}{2}n + 40 = 55$
Subtract 40 from both sides:
Multiply by 2:
1
0. $-\frac{1}{4}c - 5 = 20$
Add 5 to both sides:
Multiply by -4:
1
1. $4.8g + 9 = 33$
Subtract 9 from both sides:
Divide by 4.8:
1
2. $\frac{1}{3}p + 22 = 18$
Subtract 22 from both sides:
Multiply by 3:
1
3. $1.2y + 0.52 = 7$
Subtract 0.52 from both sides:
Divide by 1.2:
1
4. $2.5t + 24 = 14$
Subtract 24 from both sides:
Divide by 2.5:
1
5. $5j + \frac{2}{3} = -\frac{1}{6}$
Subtract from both sides:
Divide by 5:
3. Final Answer
1. $a = 11$
2. $f = 8$
3. $k = 30$
4. $b = 7$
5. $h = -6$
6. $d = -12$
7. $m = -8$
8. $z = 2$
9. $n = 30$
1
0. $c = -100$
1
1. $g = 5$
1
2. $p = -12$
1
3. $y = 5.4$
1
4. $t = -4$
1