The problem states that in trapezoid $ABCD$, $PQ$ is the midsegment. Given that $DC = 18$ and $PQ = 14$, we need to find the length of $AB$.

GeometryTrapezoidMidsegmentGeometric Formulas
2025/3/13

1. Problem Description

The problem states that in trapezoid ABCDABCD, PQPQ is the midsegment. Given that DC=18DC = 18 and PQ=14PQ = 14, we need to find the length of ABAB.

2. Solution Steps

The midsegment of a trapezoid is the segment that connects the midpoints of the non-parallel sides. The length of the midsegment is the average of the lengths of the two parallel sides. In trapezoid ABCDABCD, ABAB and DCDC are the parallel sides, and PQPQ is the midsegment. Therefore, we have the formula:
PQ=AB+DC2PQ = \frac{AB + DC}{2}
We are given that PQ=14PQ = 14 and DC=18DC = 18. We need to find ABAB. Substitute the given values into the formula:
14=AB+18214 = \frac{AB + 18}{2}
Multiply both sides of the equation by 2:
214=AB+182 * 14 = AB + 18
28=AB+1828 = AB + 18
Subtract 18 from both sides of the equation to solve for ABAB:
AB=2818AB = 28 - 18
AB=10AB = 10

3. Final Answer

The length of ABAB is
1

0. $AB = 10$

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