The problem is to solve the division problem $1200 \div 27$.

ArithmeticDivisionLong DivisionFractionsRemaindersSimplification
2025/4/13

1. Problem Description

The problem is to solve the division problem 1200÷271200 \div 27.

2. Solution Steps

We will perform long division.
First, we consider how many times 27 goes into
1
2

0. $27 \times 4 = 108$

27×5=13527 \times 5 = 135
So, 27 goes into 120 four times. We write 4 above the 0 in
1
2

0. $120 - 108 = 12$.

Next, we bring down the 0 from 1200, so we have
1
2

0. Again, 27 goes into 120 four times. We write 4 above the last 0 in

1
2
0

0. $120 - 108 = 12$.

Since we have no more digits to bring down, the remainder is
1

2. Thus, $1200 \div 27 = 44$ with a remainder of

1

2. As a mixed number, this is $44 \frac{12}{27}$.

We can simplify the fraction 1227\frac{12}{27} by dividing both numerator and denominator by 3: 1227=49\frac{12}{27} = \frac{4}{9}.
Therefore, 1200÷27=44491200 \div 27 = 44 \frac{4}{9}.

3. Final Answer

The quotient is 44 with a remainder of 12, or 444944 \frac{4}{9}.