The problem is to divide $1490$ by $28$. The image shows a long division in progress. We need to continue the long division to find the quotient and remainder.

1. Problem Description

The problem is to divide $1490$ by $28$. The image shows a long division in progress. We need to continue the long division to find the quotient and remainder.

2. Solution Steps

First we find how many times 28 goes into

1

4

9. We know that $28 \times 5 = 140$. Thus 5 is the first digit of the quotient.

Subtracting $140$ from $149$, we get $149 - 140 = 9$.

Next, we bring down the $0$ to form $90$.

Now, we find how many times $28$ goes into $90$.

$28 \times 3 = 84$.

So the next digit of the quotient is

3. Subtracting $84$ from $90$, we have $90 - 84 = 6$.

Therefore, the remainder is $6$.

The quotient is $53$.

$1490 = 28 \times 53 + 6$

3. Final Answer

The quotient is 53 and the remainder is

6. The completed long division gives $1490 \div 28 = 53$ with a remainder of $6$.