We are asked to find the surface area of a sphere to the nearest tenth. The diameter of the sphere is given as 32 m.

1. Problem Description

We are asked to find the surface area of a sphere to the nearest tenth. The diameter of the sphere is given as 32 m.

2. Solution Steps

First, we need to find the radius of the sphere. The radius is half of the diameter.

$radius = \frac{diameter}{2}$

$r = \frac{32}{2} = 16$ m

Next, we need to use the formula for the surface area of a sphere.

$Surface Area = 4\pi r^2$

Substitute $r = 16$ into the formula:

$Surface Area = 4\pi (16)^2$

$Surface Area = 4\pi (256)$

$Surface Area = 1024\pi$

Now, we need to approximate the value of the surface area to the nearest tenth.

Using $\pi \approx 3.14159$:

$Surface Area \approx 1024 \times 3.14159$

$Surface Area \approx 3216.99024$

Rounding to the nearest tenth:

$Surface Area \approx 3217.0$

3. Final Answer

The surface area of the sphere is approximately 3217.0 $m^2$.