A rectangle is placed around a semicircle. The length of the rectangle is 14 ft. We need to find the area of the shaded region (which is the area of the rectangle minus the area of the semicircle). We are given that we should use $\pi = 3.14$.

1. Problem Description

A rectangle is placed around a semicircle. The length of the rectangle is 14 ft. We need to find the area of the shaded region (which is the area of the rectangle minus the area of the semicircle). We are given that we should use $\pi = 3.14$.

2. Solution Steps

First, we need to find the dimensions of the rectangle.

The length of the rectangle is given as 14 ft.

The width of the rectangle is equal to the diameter of the semicircle. Since the length of the rectangle is the diameter of the semicircle, the radius of the semicircle is $r = \frac{14}{2} = 7$ ft.

So, the width of the rectangle is also 14 ft.

Now, we can find the area of the rectangle:

$A_{rectangle} = length \times width = 14 \times 14 = 196$ square feet.

Next, we find the area of the semicircle. The area of a full circle is $A = \pi r^2$. Since we have a semicircle, we need to divide the area of the circle by

2. $A_{semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \times 3.14 \times (7)^2 = \frac{1}{2} \times 3.14 \times 49 = \frac{1}{2} \times 153.86 = 76.93$ square feet.

Finally, we find the area of the shaded region by subtracting the area of the semicircle from the area of the rectangle:

$A_{shaded} = A_{rectangle} - A_{semicircle} = 196 - 76.93 = 119.07$ square feet.

3. Final Answer

119.07 ft^2