The problem asks us to find the area of the shaded region of a circle. The circle has center $O$ and radius of $4$ cm. The central angle of the unshaded region is $90^{\circ}$. We need to give the exact answer in terms of $\pi$, and include the correct unit in our answer.

GeometryAreaCircleSectorShaded RegionExact AnswerPi
2025/4/14

1. Problem Description

The problem asks us to find the area of the shaded region of a circle. The circle has center OO and radius of 44 cm. The central angle of the unshaded region is 9090^{\circ}. We need to give the exact answer in terms of π\pi, and include the correct unit in our answer.

2. Solution Steps

First, we calculate the area of the entire circle. The formula for the area of a circle is:
A=πr2A = \pi r^2
where rr is the radius of the circle. In this case, r=4r = 4 cm, so the area of the entire circle is:
A=π(4 cm)2=16π cm2A = \pi (4 \text{ cm})^2 = 16\pi \text{ cm}^2
Next, we find the area of the unshaded sector, which has a central angle of 9090^{\circ}. Since the circle has a total angle of 360360^{\circ}, the unshaded sector is 90360=14\frac{90^{\circ}}{360^{\circ}} = \frac{1}{4} of the circle. Thus, the area of the unshaded sector is:
Asector=14×16π cm2=4π cm2A_{\text{sector}} = \frac{1}{4} \times 16\pi \text{ cm}^2 = 4\pi \text{ cm}^2
The shaded area is the difference between the area of the entire circle and the area of the unshaded sector.
Ashaded=AAsector=16π cm24π cm2=12π cm2A_{\text{shaded}} = A - A_{\text{sector}} = 16\pi \text{ cm}^2 - 4\pi \text{ cm}^2 = 12\pi \text{ cm}^2

3. Final Answer

The area of the shaded region is 12π cm212\pi \text{ cm}^2.

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