The problem asks to find the area of the shaded region of a circle. The circle has a radius of $4$ cm, and the central angle of the unshaded sector is $90$ degrees. The answer should be in terms of $\pi$ and should include the correct unit.

GeometryAreaCircleSectorShaded Region
2025/4/14

1. Problem Description

The problem asks to find the area of the shaded region of a circle. The circle has a radius of 44 cm, and the central angle of the unshaded sector is 9090 degrees. The answer should be in terms of π\pi and should include the correct unit.

2. Solution Steps

First, we calculate the area of the entire circle.
The area of a circle is given by the formula:
Acircle=πr2A_{circle} = \pi r^2
where rr is the radius of the circle. In this case, the radius is 44 cm.
Acircle=π(4 cm)2=16π cm2A_{circle} = \pi (4 \text{ cm})^2 = 16\pi \text{ cm}^2
Next, we calculate the area of the unshaded sector. The central angle of the sector is 9090 degrees, which is 90360=14\frac{90}{360} = \frac{1}{4} of the entire circle.
The area of the sector is given by:
Asector=central angle360×AcircleA_{sector} = \frac{\text{central angle}}{360} \times A_{circle}
Asector=90360×16π cm2=14×16π cm2=4π cm2A_{sector} = \frac{90}{360} \times 16\pi \text{ cm}^2 = \frac{1}{4} \times 16\pi \text{ cm}^2 = 4\pi \text{ cm}^2
Now, we subtract the area of the unshaded sector from the area of the entire circle to find the area of the shaded region.
Ashaded=AcircleAsectorA_{shaded} = A_{circle} - A_{sector}
Ashaded=16π cm24π cm2=12π cm2A_{shaded} = 16\pi \text{ cm}^2 - 4\pi \text{ cm}^2 = 12\pi \text{ cm}^2

3. Final Answer

12π cm212\pi \text{ cm}^2

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