The ratio of blue tiles to green tiles is given as $(2x+1):(4x+9)$. It is also given that $\frac{1}{4}$ of the tiles are blue. We are asked to find the value of $x$.

AlgebraRatioLinear EquationsAlgebraic Manipulation
2025/3/14

1. Problem Description

The ratio of blue tiles to green tiles is given as (2x+1):(4x+9)(2x+1):(4x+9). It is also given that 14\frac{1}{4} of the tiles are blue. We are asked to find the value of xx.

2. Solution Steps

Let the number of blue tiles be 2x+12x+1 and the number of green tiles be 4x+94x+9. The total number of tiles is the sum of the number of blue and green tiles, which is (2x+1)+(4x+9)=6x+10(2x+1) + (4x+9) = 6x+10.
Since 14\frac{1}{4} of the tiles are blue, we have:
Number of blue tilesTotal number of tiles=14\frac{\text{Number of blue tiles}}{\text{Total number of tiles}} = \frac{1}{4}
2x+16x+10=14\frac{2x+1}{6x+10} = \frac{1}{4}
Cross-multiplying, we get:
4(2x+1)=1(6x+10)4(2x+1) = 1(6x+10)
8x+4=6x+108x+4 = 6x+10
Subtract 6x6x from both sides:
8x6x+4=6x6x+108x - 6x + 4 = 6x - 6x + 10
2x+4=102x + 4 = 10
Subtract 4 from both sides:
2x+44=1042x + 4 - 4 = 10 - 4
2x=62x = 6
Divide both sides by 2:
2x2=62\frac{2x}{2} = \frac{6}{2}
x=3x=3

3. Final Answer

x=3x = 3

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