The problem states that the surface area of a sphere is four times the area of its largest cross section. We need to find the approximate surface area of a cantaloupe that is 6 inches in diameter and round the answer to the nearest square inch. We are given that we should use $3.14$ for $\pi$.

1. Problem Description

The problem states that the surface area of a sphere is four times the area of its largest cross section. We need to find the approximate surface area of a cantaloupe that is 6 inches in diameter and round the answer to the nearest square inch. We are given that we should use $3.14$ for $\pi$.

2. Solution Steps

The formula for the surface area of a sphere is:

$A = 4 \pi r^2$

where $A$ is the surface area and $r$ is the radius.

We are given the diameter of the cantaloupe, which is 6 inches. The radius is half of the diameter.

$r = \frac{6}{2} = 3$ inches

Now we can calculate the surface area using the formula and the given value for $\pi$.

$A = 4 \pi r^2 = 4 \times 3.14 \times (3)^2$

$A = 4 \times 3.14 \times 9$

$A = 12.56 \times 9$

$A = 113.04$ square inches.

We need to round the answer to the nearest square inch.

$A \approx 113$ square inches

3. Final Answer

113 square inches