Determine whether the equation $y = 5x^2 + 2x$ is proportional or not.

AlgebraProportionalityFunctionsQuadratic Equations
2025/4/16

1. Problem Description

Determine whether the equation y=5x2+2xy = 5x^2 + 2x is proportional or not.

2. Solution Steps

A proportional relationship can be expressed in the form y=kxy = kx, where kk is the constant of proportionality. In a proportional relationship, yy is directly proportional to xx.
The given equation is y=5x2+2xy = 5x^2 + 2x. We can see that the equation has a term with x2x^2 and a term with xx. For the equation to represent a proportional relationship, it should be in the form y=kxy=kx. The equation given is not in that form. If we tried to force it into the y=kxy=kx form, we would have
k=yx=5x2+2xx=5x+2k = \frac{y}{x} = \frac{5x^2 + 2x}{x} = 5x + 2.
Since kk depends on xx, it is not a constant.
Another way to think about this is that a proportional relationship must pass through the origin (0,0)(0,0). Let's plug in x=0x=0 into the equation:
y=5(0)2+2(0)=0y = 5(0)^2 + 2(0) = 0
The equation passes through the origin. However, this is not enough to determine if it is proportional.
Let's consider two different values of xx.
If x=1x=1, y=5(1)2+2(1)=5+2=7y = 5(1)^2 + 2(1) = 5+2 = 7.
If x=2x=2, y=5(2)2+2(2)=5(4)+4=20+4=24y = 5(2)^2 + 2(2) = 5(4) + 4 = 20+4 = 24.
For the relationship to be proportional, yx\frac{y}{x} must be constant.
In the first case, yx=71=7\frac{y}{x} = \frac{7}{1} = 7.
In the second case, yx=242=12\frac{y}{x} = \frac{24}{2} = 12.
Since the ratio is not constant, the equation is not proportional.

3. Final Answer

Non-Proportional

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