The problem is to solve the system of two equations: $b = -a$ $-12 = -6a$ for the variables $a$ and $b$.

AlgebraLinear EquationsSystem of EquationsSolving Equations
2025/4/17

1. Problem Description

The problem is to solve the system of two equations:
b=ab = -a
12=6a-12 = -6a
for the variables aa and bb.

2. Solution Steps

We have two equations:
(1) b=ab = -a
(2) 12=6a-12 = -6a
From equation (2), we can solve for aa:
12=6a-12 = -6a
Divide both sides by 6-6:
126=6a6\frac{-12}{-6} = \frac{-6a}{-6}
2=a2 = a
a=2a = 2
Now that we have a=2a = 2, we can substitute this value into equation (1) to find bb:
b=ab = -a
b=2b = -2

3. Final Answer

a=2a = 2
b=2b = -2

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