The problem asks for the probability that the next pizza made is not a cheese pizza, given that Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.

1. Problem Description

The problem asks for the probability that the next pizza made is not a cheese pizza, given that Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.

2. Solution Steps

First, we need to find the total number of pizzas made yesterday.

Total pizzas = Cheese pizzas + Veggie pizzas + Pepperoni pizzas + Sausage pizzas

Total pizzas = $21 + 14 + 23 + 14 = 72$

Next, we need to find the number of pizzas that were not cheese pizzas.

Not cheese pizzas = Total pizzas - Cheese pizzas

Not cheese pizzas = $72 - 21 = 51$

Then, we can find the probability that the next pizza made is not a cheese pizza.

$P(\text{not cheese}) = \frac{\text{Number of not cheese pizzas}}{\text{Total number of pizzas}}$

$P(\text{not cheese}) = \frac{51}{72}$

Now, we convert the fraction to a percentage.

$\frac{51}{72} \approx 0.708333$

$0.708333 \times 100 = 70.8333 \%$

Rounding to the nearest whole number, we get $71\%$.

3. Final Answer

$71\%$