We are asked to simplify the expression $3^{x+2} - 6 \times 3^x + 5 \times 3^{x-2}$.

AlgebraExponentsSimplificationAlgebraic Manipulation
2025/4/17

1. Problem Description

We are asked to simplify the expression 3x+26×3x+5×3x23^{x+2} - 6 \times 3^x + 5 \times 3^{x-2}.

2. Solution Steps

We can rewrite the expression by factoring out 3x23^{x-2}:
3x+26×3x+5×3x2=34×3x26×32×3x2+5×3x23^{x+2} - 6 \times 3^x + 5 \times 3^{x-2} = 3^4 \times 3^{x-2} - 6 \times 3^2 \times 3^{x-2} + 5 \times 3^{x-2}.
Factoring out 3x23^{x-2}, we have
3x2(346×32+5)3^{x-2} (3^4 - 6 \times 3^2 + 5).
Now we evaluate the expression inside the parentheses:
34=813^4 = 81 and 32=93^2 = 9.
So, we have
3x2(816×9+5)=3x2(8154+5)3^{x-2} (81 - 6 \times 9 + 5) = 3^{x-2} (81 - 54 + 5).
Calculating the expression inside the parentheses, we get
8154+5=27+5=3281 - 54 + 5 = 27 + 5 = 32.
Therefore, the expression becomes
32×3x232 \times 3^{x-2}.

3. Final Answer

32×3x232 \times 3^{x-2}

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