The problem is to solve for $x$ and $y$ in the equation $\frac{1}{2}x + \frac{3}{4}y = 5$. However, since we only have one equation and two variables, we can only express one variable in terms of the other.

AlgebraLinear EquationsSolving EquationsSystems of EquationsVariable Isolation
2025/4/17

1. Problem Description

The problem is to solve for xx and yy in the equation 12x+34y=5\frac{1}{2}x + \frac{3}{4}y = 5. However, since we only have one equation and two variables, we can only express one variable in terms of the other.

2. Solution Steps

We want to isolate xx or yy. Let's isolate xx.
We have 12x+34y=5\frac{1}{2}x + \frac{3}{4}y = 5.
Subtract 34y\frac{3}{4}y from both sides:
12x=534y\frac{1}{2}x = 5 - \frac{3}{4}y
Multiply both sides by 2:
x=2(534y)x = 2(5 - \frac{3}{4}y)
x=1064yx = 10 - \frac{6}{4}y
x=1032yx = 10 - \frac{3}{2}y
Alternatively, let's isolate yy.
We have 12x+34y=5\frac{1}{2}x + \frac{3}{4}y = 5.
Subtract 12x\frac{1}{2}x from both sides:
34y=512x\frac{3}{4}y = 5 - \frac{1}{2}x
Multiply both sides by 43\frac{4}{3}:
y=43(512x)y = \frac{4}{3}(5 - \frac{1}{2}x)
y=20346xy = \frac{20}{3} - \frac{4}{6}x
y=20323xy = \frac{20}{3} - \frac{2}{3}x

3. Final Answer

Since there is only one equation, we can only express xx in terms of yy, or yy in terms of xx.
x=1032yx = 10 - \frac{3}{2}y
or
y=20323xy = \frac{20}{3} - \frac{2}{3}x

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