The problem asks us to find the probability of selecting an apple from a pantry containing 4 apples and 5 bananas. We are asked to round the answer to 2 decimal places if necessary.

1. Problem Description

The problem asks us to find the probability of selecting an apple from a pantry containing 4 apples and 5 bananas. We are asked to round the answer to 2 decimal places if necessary.

2. Solution Steps

The probability of an event is calculated as the number of favorable outcomes divided by the total number of possible outcomes.

In this case, the favorable outcome is selecting an apple, and the total number of possible outcomes is selecting any fruit (apple or banana).

Number of apples = 4

Number of bananas = 5

Total number of fruits = Number of apples + Number of bananas = 4 + 5 = 9

The probability of selecting an apple, $P(\text{apple})$, is:

$P(\text{apple}) = \frac{\text{Number of apples}}{\text{Total number of fruits}}$

$P(\text{apple}) = \frac{4}{9}$

To convert this fraction to a decimal, we divide 4 by 9:

$4 \div 9 = 0.4444...$

Rounding this to two decimal places, we get 0.

4

4.

3. Final Answer

$0.44$