The image shows the division problem $31 \overline{)6799}$. We need to verify the provided solution and find the remainder.

1. Problem Description

The image shows the division problem $31 \overline{)6799}$. We need to verify the provided solution and find the remainder.

2. Solution Steps

The provided solution seems to have some errors, so let's re-evaluate it.

* First, we divide 67 by

3

1. $31 \times 2 = 62$. So, 2 is the first digit of the quotient. $67 - 62 = 5$.

* Bring down the next digit, 9, to get

5

9. Now, divide 59 by

3

1. $31 \times 1 = 31$. So, 1 is the next digit of the quotient. $59 - 31 = 28$.

* Bring down the last digit, 9, to get

2

8

9. Now, divide 289 by

3

1. $31 \times 9 = 279$. So, 9 is the last digit of the quotient. $289 - 279 = 10$.

Thus, the quotient is 219 and the remainder is

1

0.

Formula:

Dividend = Divisor * Quotient + Remainder

$6799 = 31 \times 219 + 10$

$6799 = 6789 + 10$

$6799 = 6799$

The solution on the image attempts the same approach but contains errors.

3. Final Answer

The quotient is 219 and the remainder is 10.