A rectangle $PQRS$ has dimensions $20$ cm by $(10+10)$ cm $= 20$ cm. A square of side $x$ cm is cut out from the rectangle. The area of the shaded portion is given as $484$ cm$^2$. We need to find the value of $x$.

GeometryAreaRectangleSquareAlgebraic Equations
2025/4/19

1. Problem Description

A rectangle PQRSPQRS has dimensions 2020 cm by (10+10)(10+10) cm =20= 20 cm. A square of side xx cm is cut out from the rectangle. The area of the shaded portion is given as 484484 cm2^2. We need to find the value of xx.

2. Solution Steps

First, we calculate the area of the rectangle PQRSPQRS.
Area of rectangle PQRSPQRS = length ×\times width = 20×(10+10)=20×20=40020 \times (10+10) = 20 \times 20 = 400 cm2^2.
The area of the square that is cut out is x2x^2 cm2^2.
Area of shaded portion = Area of rectangle - Area of square.
We are given that the area of the shaded portion is 484484 cm2^2.
So, 400x2=484400 - x^2 = 484 is incorrect.
Looking at the figure, we see that the length of rectangle is 10+10=2010 + 10 = 20 cm and width is 2020 cm. Also, the square that is cut off has sides equal to xx.
Area of the rectangle = 20×20=40020 \times 20 = 400 cm2^2.
Area of the square = x×x=x2x \times x = x^2 cm2^2.
Area of shaded region = Area of rectangle - Area of square
484484 = 400+area400 + area which is not right, the area of shaded portion cannot be greater than the total area.
Let the rectangle be 2020 by 2020, and the square has sides xx. The shaded area is
4
8

4. $20 \times 20 - x^2 = 400-x^2$, which equals the shaded area. But 484 is greater than

4
0

0. There must be some mistake somewhere.

The length of rectangle PQRSPQRS is 10 cm+10 cm=20 cm10 \text{ cm} + 10 \text{ cm} = 20 \text{ cm} and the width is 20 cm20 \text{ cm}. So the area of the rectangle PQRSPQRS is 20 cm×20 cm=400 cm220 \text{ cm} \times 20 \text{ cm} = 400 \text{ cm}^2.
The area of the square cut out is x2 cm2x^2 \text{ cm}^2.
So, Area of shaded portion = Area of rectangle - Area of square
484=400x2484 = 400 - x^2 which is wrong because we end up with x2=84x^2 = -84, and we want the real solution.
Upon looking at the figure, it appears the square is cut into the original rectangle. That implies
Area of rectangle - area of square = Shaded area.
20×(10+10)x2=48420 \times (10 + 10) - x^2 = 484
400x2=484400 - x^2 = 484
x2=400484=84x^2 = 400 - 484 = -84
Which is not a real value.
I realized that my mistake is the value
4
8

4. Let us assume instead the shaded area is $A = 384 cm^2$.

400x2=384400 - x^2 = 384
x2=400384x^2 = 400 - 384
x2=16x^2 = 16
x=4x = 4 cm.
Assuming the printed value is 384 instead of 484:
Area of shaded portion = Area of rectangle PQRSPQRS - Area of square
384=(20×20)x2384 = (20 \times 20) - x^2
384=400x2384 = 400 - x^2
x2=400384x^2 = 400 - 384
x2=16x^2 = 16
x=16x = \sqrt{16}
x=4x = 4 cm
However, the problem states that the shaded area is 484 cm2484 \text{ cm}^2. This is not possible. If we assume the problem is printed wrong, and the shaded region is actually 384, the answer would be
4.

3. Final Answer

Due to inconsistency of information, there is no real solution. If the area was 384 cm2^2, then x=4x = 4 cm. With the information as provided, there is no answer. There appears to be a printing error on the value.

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