Find the coordinates of the foci of the ellipse given by the equation $\frac{x^2}{30} + \frac{y^2}{5} = 1$.

GeometryEllipseConic SectionsFoci
2025/6/14

1. Problem Description

Find the coordinates of the foci of the ellipse given by the equation x230+y25=1\frac{x^2}{30} + \frac{y^2}{5} = 1.

2. Solution Steps

The equation of the ellipse is given by x230+y25=1\frac{x^2}{30} + \frac{y^2}{5} = 1. Since 30>530 > 5, the major axis is along the x-axis. The equation has the form x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, where a2=30a^2 = 30 and b2=5b^2 = 5.
We need to find cc, where c2=a2b2c^2 = a^2 - b^2.
c2=a2b2c^2 = a^2 - b^2
c2=305c^2 = 30 - 5
c2=25c^2 = 25
c=25c = \sqrt{25}
c=5c = 5
Since the major axis is along the x-axis, the foci are at (±c,0)(\pm c, 0). Therefore, the foci are at (±5,0)(\pm 5, 0).

3. Final Answer

(±5, 0)

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