Find the coordinates of the foci of the hyperbola $\frac{x^2}{16} - \frac{y^2}{9} = 1$.

1. Problem Description

Find the coordinates of the foci of the hyperbola $\frac{x^2}{16} - \frac{y^2}{9} = 1$.

2. Solution Steps

The standard form of a hyperbola is $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$.

In this case, we have $a^2 = 16$ and $b^2 = 9$.

Thus, $a = 4$ and $b = 3$.

To find the foci, we need to calculate $c$, where $c^2 = a^2 + b^2$.

$c^2 = a^2 + b^2$

$c^2 = 16 + 9$

$c^2 = 25$

$c = \sqrt{25}$

$c = 5$

Since the hyperbola is in the form $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$, the foci are located on the x-axis. The coordinates of the foci are $(\pm c, 0)$.

Therefore, the coordinates of the foci are $(\pm 5, 0)$.

3. Final Answer

(±5, 0)