The problem asks to divide the polynomial $47108m^3n - 122mn + 48mn^2$ by $2mn$.

AlgebraPolynomial DivisionAlgebraic Manipulation
2025/4/21

1. Problem Description

The problem asks to divide the polynomial 47108m3n122mn+48mn247108m^3n - 122mn + 48mn^2 by 2mn2mn.

2. Solution Steps

We need to divide each term of the polynomial by 2mn2mn.
First term: 47108m3n2mn=471082m3mnn=23554m311=23554m2\frac{47108m^3n}{2mn} = \frac{47108}{2} \cdot \frac{m^3}{m} \cdot \frac{n}{n} = 23554m^{3-1} \cdot 1 = 23554m^2.
Second term: 122mn2mn=1222mmnn=6111=61\frac{-122mn}{2mn} = \frac{-122}{2} \cdot \frac{m}{m} \cdot \frac{n}{n} = -61 \cdot 1 \cdot 1 = -61.
Third term: 48mn22mn=482mmn2n=241n21=24n\frac{48mn^2}{2mn} = \frac{48}{2} \cdot \frac{m}{m} \cdot \frac{n^2}{n} = 24 \cdot 1 \cdot n^{2-1} = 24n.
Combining these terms, we get 23554m261+24n23554m^2 - 61 + 24n.

3. Final Answer

23554m261+24n23554m^2 - 61 + 24n

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