The problem asks to find the range of the function $g(x) = x^2 + 9$ for the domain $\{-2, -1, 0, 1, 2\}$.

1. Problem Description

The problem asks to find the range of the function $g(x) = x^2 + 9$ for the domain $\{-2, -1, 0, 1, 2\}$.

2. Solution Steps

To find the range, we need to evaluate the function $g(x)$ for each value in the given domain.

* For $x = -2$, $g(-2) = (-2)^2 + 9 = 4 + 9 = 13$.

* For $x = -1$, $g(-1) = (-1)^2 + 9 = 1 + 9 = 10$.

* For $x = 0$, $g(0) = (0)^2 + 9 = 0 + 9 = 9$.

* For $x = 1$, $g(1) = (1)^2 + 9 = 1 + 9 = 10$.

* For $x = 2$, $g(2) = (2)^2 + 9 = 4 + 9 = 13$.

The range is the set of all output values, which are $\{13, 10, 9, 10, 13\}$. We write this as a set, listing each distinct value only once. So the range is $\{9, 10, 13\}$.

3. Final Answer

{9, 10, 13}