We are asked to simplify the following inequalities: (a) $2x + 3 < 7$ (b) $5t + 6 > 21$ (c) $3x - 5 \ge 16$ (d) $1.5z + 1 \le 2$

AlgebraInequalitiesLinear InequalitiesSolving Inequalities
2025/4/22

1. Problem Description

We are asked to simplify the following inequalities:
(a) 2x+3<72x + 3 < 7
(b) 5t+6>215t + 6 > 21
(c) 3x5163x - 5 \ge 16
(d) 1.5z+121.5z + 1 \le 2

2. Solution Steps

(a) 2x+3<72x + 3 < 7
Subtract 3 from both sides:
2x+33<732x + 3 - 3 < 7 - 3
2x<42x < 4
Divide both sides by 2:
2x2<42\frac{2x}{2} < \frac{4}{2}
x<2x < 2
(b) 5t+6>215t + 6 > 21
Subtract 6 from both sides:
5t+66>2165t + 6 - 6 > 21 - 6
5t>155t > 15
Divide both sides by 5:
5t5>155\frac{5t}{5} > \frac{15}{5}
t>3t > 3
(c) 3x5163x - 5 \ge 16
Add 5 to both sides:
3x5+516+53x - 5 + 5 \ge 16 + 5
3x213x \ge 21
Divide both sides by 3:
3x3213\frac{3x}{3} \ge \frac{21}{3}
x7x \ge 7
(d) 1.5z+121.5z + 1 \le 2
Subtract 1 from both sides:
1.5z+11211.5z + 1 - 1 \le 2 - 1
1.5z11.5z \le 1
Divide both sides by 1.5:
1.5z1.511.5\frac{1.5z}{1.5} \le \frac{1}{1.5}
z132z \le \frac{1}{\frac{3}{2}}
z23z \le \frac{2}{3}

3. Final Answer

(a) x<2x < 2
(b) t>3t > 3
(c) x7x \ge 7
(d) z23z \le \frac{2}{3}

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