The problem is to solve the logarithmic equation $\log_{3} x = 2$ for $x$.

AlgebraLogarithmsExponential FormEquation Solving
2025/4/22

1. Problem Description

The problem is to solve the logarithmic equation log3x=2\log_{3} x = 2 for xx.

2. Solution Steps

To solve for xx in the equation log3x=2\log_{3} x = 2, we can rewrite the equation in exponential form. The general form of a logarithmic equation is logba=c\log_b a = c, which can be rewritten as bc=ab^c = a. Applying this to the given equation, we have:
log3x=2\log_{3} x = 2
Converting the logarithmic equation to exponential form, we get
32=x3^2 = x
Calculating 323^2, we have
x=9x = 9

3. Final Answer

x=9x = 9

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