We are given the following information: $a+b+c = 15$ $a^2 + b^2 + c^2 = 83$ We are asked to find the value of $ab+bc+ca$.

AlgebraAlgebraic EquationsExpansionProblem Solving
2025/4/22

1. Problem Description

We are given the following information:
a+b+c=15a+b+c = 15
a2+b2+c2=83a^2 + b^2 + c^2 = 83
We are asked to find the value of ab+bc+caab+bc+ca.

2. Solution Steps

We can use the formula:
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
Substitute the given values into the formula:
(15)2=83+2(ab+bc+ca)(15)^2 = 83 + 2(ab+bc+ca)
225=83+2(ab+bc+ca)225 = 83 + 2(ab+bc+ca)
22583=2(ab+bc+ca)225 - 83 = 2(ab+bc+ca)
142=2(ab+bc+ca)142 = 2(ab+bc+ca)
ab+bc+ca=1422ab+bc+ca = \frac{142}{2}
ab+bc+ca=71ab+bc+ca = 71

3. Final Answer

The value of ab+bc+caab+bc+ca is 71.

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