The problem asks us to find the coordinates of the midpoint of the line segment AB, where point A has coordinates $(-13, -9)$ and point B has coordinates $(1, 15)$.

1. Problem Description

The problem asks us to find the coordinates of the midpoint of the line segment AB, where point A has coordinates $(-13, -9)$ and point B has coordinates $(1, 15)$.

2. Solution Steps

To find the midpoint of a line segment with endpoints $(x_1, y_1)$ and $(x_2, y_2)$, we use the midpoint formula:

$$\text{Midpoint} = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$$

In this case, we have $x_1 = -13$, $y_1 = -9$, $x_2 = 1$, and $y_2 = 15$.

Plugging these values into the midpoint formula, we get:

$$\text{Midpoint} = \left(\frac{-13 + 1}{2}, \frac{-9 + 15}{2}\right)$$

$$\text{Midpoint} = \left(\frac{-12}{2}, \frac{6}{2}\right)$$

$$\text{Midpoint} = (-6, 3)$$

3. Final Answer

The coordinates of the midpoint of line AB are $(-6, 3)$.