The image presents three math problems: 1. Evaluate $5^3 \times \frac{1}{5^2}$.

AlgebraExponentsSimplificationPolynomialsQuadratic EquationsFactoringFOIL Method
2025/4/22

1. Problem Description

The image presents three math problems:

1. Evaluate $5^3 \times \frac{1}{5^2}$.

2. Expand and simplify $(2a + 3)(3a - 4)$.

3. Solve the equation $4x^2 = 9x$.

2. Solution Steps

Problem 1: Evaluate 53×1525^3 \times \frac{1}{5^2}.
We can rewrite the expression as:
53×152=53525^3 \times \frac{1}{5^2} = \frac{5^3}{5^2}.
Using the property aman=amn\frac{a^m}{a^n} = a^{m-n}, we have:
5352=532=51=5\frac{5^3}{5^2} = 5^{3-2} = 5^1 = 5.
Problem 2: Expand and simplify (2a+3)(3a4)(2a + 3)(3a - 4).
We use the distributive property (FOIL method):
(2a+3)(3a4)=2a(3a)+2a(4)+3(3a)+3(4)(2a + 3)(3a - 4) = 2a(3a) + 2a(-4) + 3(3a) + 3(-4)
=6a28a+9a12= 6a^2 - 8a + 9a - 12
=6a2+a12= 6a^2 + a - 12.
Problem 3: Solve the equation 4x2=9x4x^2 = 9x.
Subtract 9x9x from both sides:
4x29x=04x^2 - 9x = 0.
Factor out xx:
x(4x9)=0x(4x - 9) = 0.
So either x=0x = 0 or 4x9=04x - 9 = 0.
If 4x9=04x - 9 = 0, then 4x=94x = 9, so x=94x = \frac{9}{4}.
Thus, the solutions are x=0x = 0 or x=94x = \frac{9}{4}.

3. Final Answer

1. 5

2. $6a^2 + a - 12$

3. $x = 0$ or $x = \frac{9}{4}$

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