The problem asks us to factorise the expression $2ab + xy - 2ay - bx$ completely.

AlgebraFactorizationAlgebraic ExpressionsGrouping
2025/4/22

1. Problem Description

The problem asks us to factorise the expression 2ab+xy2aybx2ab + xy - 2ay - bx completely.

2. Solution Steps

To factorise the given expression, we can use the grouping method.
First, rearrange the terms:
2ab2aybx+xy2ab - 2ay - bx + xy.
Group the first two terms and the last two terms:
(2ab2ay)+(bx+xy)(2ab - 2ay) + (-bx + xy).
Factor out the common factors from each group:
2a(by)x(by)2a(b - y) - x(b - y).
Now, we can see that (by)(b - y) is a common factor in both terms:
(2ax)(by)(2a - x)(b - y).
This is the completely factorised form.

3. Final Answer

(2ax)(by)(2a - x)(b - y)

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