The problem asks us to sketch the graph of the line given by the equation $y = \frac{1}{4}x - 3$.

AlgebraLinear EquationsGraphingSlope-intercept form
2025/4/23

1. Problem Description

The problem asks us to sketch the graph of the line given by the equation y=14x3y = \frac{1}{4}x - 3.

2. Solution Steps

The given equation is in the slope-intercept form, which is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
In our case, m=14m = \frac{1}{4} and b=3b = -3. This means that the line intersects the y-axis at the point (0,3)(0, -3).
To find another point on the line, we can choose a value for xx and calculate the corresponding yy value.
Let's choose x=4x = 4. Then y=14(4)3=13=2y = \frac{1}{4}(4) - 3 = 1 - 3 = -2. So, another point on the line is (4,2)(4, -2).
Now we have two points: (0,3)(0, -3) and (4,2)(4, -2).
We can plot these points on the coordinate plane and draw a line through them to sketch the graph of the equation.

3. Final Answer

The graph is a line passing through the points (0,3)(0, -3) and (4,2)(4, -2). (Note: I cannot actually sketch the graph here, but this description allows you to do so.)

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