We are given two functions, $f(x) = log_{10}x$ and $f(x) = -\frac{1}{2}log_{10}x - 5$. We need to determine the transformations that turn the first function into the second function.

AlgebraLogarithmsFunction TransformationsVertical CompressionReflectionVertical Translation
2025/4/23

1. Problem Description

We are given two functions, f(x)=log10xf(x) = log_{10}x and f(x)=12log10x5f(x) = -\frac{1}{2}log_{10}x - 5. We need to determine the transformations that turn the first function into the second function.

2. Solution Steps

We start with the function f(x)=log10xf(x) = log_{10}x.
First, consider the transformation f(x)f(x) to 12f(x)-\frac{1}{2}f(x).
Multiplying the function by 1-1 reflects the function across the x-axis.
Multiplying the function by 12\frac{1}{2} vertically compresses the function by a factor of 12\frac{1}{2}.
Therefore, 12f(x)=12log10x-\frac{1}{2}f(x) = -\frac{1}{2}log_{10}x means a reflection across the x-axis and a vertical compression by a factor of 12\frac{1}{2}.
Next, consider the transformation 12log10x-\frac{1}{2}log_{10}x to 12log10x5-\frac{1}{2}log_{10}x - 5.
Subtracting 5 from the function results in a vertical translation 5 units down.
Therefore, the transformations are:

1. Reflection about the x-axis.

2. Vertical compression by a factor of $\frac{1}{2}$.

3. Vertical translation 5 units down.

3. Final Answer

Reflection about the x-axis, vertical compression by a factor of 12\frac{1}{2}, vertical translation 5 units down.