Solve the equation $2\log{x} - \log{4} = 2$. We assume the base of the logarithm is 10.

AlgebraLogarithmsEquationsAlgebraic ManipulationSolving Equations
2025/4/23

1. Problem Description

Solve the equation 2logxlog4=22\log{x} - \log{4} = 2. We assume the base of the logarithm is
1
0.

2. Solution Steps

First, we can use the logarithm property nloga=logann\log{a} = \log{a^n} to rewrite the first term:
2logx=logx22\log{x} = \log{x^2}
So the equation becomes:
logx2log4=2\log{x^2} - \log{4} = 2
Next, we use the logarithm property logalogb=logab\log{a} - \log{b} = \log{\frac{a}{b}} to combine the terms on the left:
logx24=2\log{\frac{x^2}{4}} = 2
Since the logarithm is base 10, we can rewrite the equation in exponential form:
x24=102\frac{x^2}{4} = 10^2
x24=100\frac{x^2}{4} = 100
Multiply both sides by 4:
x2=400x^2 = 400
Take the square root of both sides:
x=±400x = \pm\sqrt{400}
x=±20x = \pm 20
Since the logarithm of a negative number is undefined, we only consider the positive solution.
x=20x = 20

3. Final Answer

20

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