We are given a geometric sequence $\{a_n\}$ with $a_1 = 4$ and $a_2 = 20$. We need to find the sum of the first $n$ terms, $S_n$.

AlgebraSequences and SeriesGeometric SequenceSum of Geometric Series
2025/4/24

1. Problem Description

We are given a geometric sequence {an}\{a_n\} with a1=4a_1 = 4 and a2=20a_2 = 20. We need to find the sum of the first nn terms, SnS_n.

2. Solution Steps

First, we find the common ratio rr of the geometric sequence. Since a2=a1ra_2 = a_1 \cdot r, we have
r=a2a1=204=5r = \frac{a_2}{a_1} = \frac{20}{4} = 5
The formula for the sum of the first nn terms of a geometric sequence is:
Sn=a1(rn1)r1S_n = \frac{a_1(r^n - 1)}{r - 1}
Substituting the given values, we have
Sn=4(5n1)51=4(5n1)4=5n1S_n = \frac{4(5^n - 1)}{5 - 1} = \frac{4(5^n - 1)}{4} = 5^n - 1

3. Final Answer

The sum of the first nn terms is Sn=5n1S_n = 5^n - 1. Therefore, the answer is A. 5n15^n - 1.

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