We are given two exercises. Exercise 2: $f$ is a linear function such that $f(7) = 14$. We need to: 1. Find the expression of $f(x)$.
2025/4/25
1. Problem Description
We are given two exercises.
Exercise 2:
is a linear function such that . We need to:
1. Find the expression of $f(x)$.
2. Find the number whose image is $21$ by the function $f$.
3. Draw the line $(D)$ representing the graph of the function $f$.
Exercise 3:
is an affine function such that and . We need to:
1. Find the expression of $g(x)$.
2. Calculate $g(1)$ and $g(3)$.
3. Find the number whose image is $21$ by the function $g$.
4. Draw the line $(\Delta)$ representing the graph of the function $g$.
2. Solution Steps
Exercise 2:
1. Since $f$ is a linear function, it has the form $f(x) = ax$ for some constant $a$. We are given that $f(7) = 14$. Therefore, $7a = 14$, which implies $a = 2$. Thus, $f(x) = 2x$.
2. We want to find $x$ such that $f(x) = 21$. Thus, $2x = 21$, which implies $x = \frac{21}{2} = 10.5$.
3. The line $(D)$ representing the graph of $f(x) = 2x$ passes through the points $(0, 0)$ and $(7, 14)$. You can draw this line on a graph.
Exercise 3:
1. Since $g$ is an affine function, it has the form $g(x) = ax + b$ for some constants $a$ and $b$. We are given that $g(0) = 3$ and $g(2) = 7$.
Using , we have , which implies .
Using , we have . Substituting , we get , which implies , so .
Thus, .
2. We need to calculate $g(1)$ and $g(3)$.
.
.
3. We want to find $x$ such that $g(x) = 21$. Thus, $2x + 3 = 21$, which implies $2x = 18$, so $x = 9$.
4. The line $(\Delta)$ representing the graph of $g(x) = 2x + 3$ passes through the points $(0, 3)$ and $(2, 7)$. You can draw this line on a graph.
3. Final Answer
Exercise 2:
1. $f(x) = 2x$
2. $x = 10.5$
3. Draw the line passing through (0,0) and (7,14).
Exercise 3: