The problem asks to find the area of the given figure, which is a composite shape made up of a triangle, rectangles, and squares.

1. Problem Description

The problem asks to find the area of the given figure, which is a composite shape made up of a triangle, rectangles, and squares.

2. Solution Steps

First, we divide the figure into smaller rectangles, a square, and a right triangle.

The area of each part can be calculated using the standard formulas.

a. Triangle on the left:

Base = 6 ft

Height = 5 ft

Area of triangle = $\frac{1}{2} \times base \times height = \frac{1}{2} \times 6 \times 5 = 15$ square feet

b. Rectangle below the triangle:

Length = 3 ft

Width = 6 ft

Area of rectangle = $length \times width = 3 \times 6 = 18$ square feet

c. Rectangle in the middle:

Length = 8 ft

Width = 6 ft

Area of rectangle = $length \times width = 8 \times 6 = 48$ square feet

d. Rectangle on the right:

Length = 3 ft

Width = 9 ft

Area of rectangle = $length \times width = 3 \times 9 = 27$ square feet

e. Square on top right.

Length = 5 ft

Width = 5 ft

Area of the square = $length \times width = 5 \times 5 = 25$ square feet

To calculate the area of the whole shape we subtract the square.

Total Area = Area of triangle + Area of rectangle (below the triangle) + Area of rectangle (middle) + Area of rectangle (right) + Area of square

Total Area = 15 + 18 + 48 + 27 + 25 = 133 square feet

3. Final Answer

133 square feet