The problem has two parts. The first part deals with a linear function $f(x)$ represented by the line $(D)$. We are given a table with some $x$ values and corresponding $f(x)$ values, with some missing entries that we need to fill in. Then, we need to determine the expression for $f(x)$. The second part deals with another linear function $g(x)$ represented by the line $(\Delta)$. We need to find the coefficient of $g(x)$ and then determine the expression for $g(x)$.

AlgebraLinear FunctionsFunction AnalysisTable CompletionEquation of a LineCoefficients
2025/4/26

1. Problem Description

The problem has two parts. The first part deals with a linear function f(x)f(x) represented by the line (D)(D). We are given a table with some xx values and corresponding f(x)f(x) values, with some missing entries that we need to fill in. Then, we need to determine the expression for f(x)f(x). The second part deals with another linear function g(x)g(x) represented by the line (Δ)(\Delta). We need to find the coefficient of g(x)g(x) and then determine the expression for g(x)g(x).

2. Solution Steps

Part 1:
a) Completing the table for f(x)f(x).
We are given that f(2)=3f(2) = 3 and f(3)=3f(-3) = -3. Since f(x)f(x) is a linear function, we can write it as f(x)=axf(x) = ax for some constant aa.
Using the given information, f(2)=2a=3f(2) = 2a = 3, so a=32a = \frac{3}{2}. Thus, f(x)=32xf(x) = \frac{3}{2}x.
Now we can find the missing values in the table:
If x=2x = -2, then f(2)=32(2)=3f(-2) = \frac{3}{2}(-2) = -3.
We already have f(2)=3f(2)=3 and f(3)=3f(-3) = -3
The completed table is:
| xx | 2 | -2 | -3 |
| ------- | ---- | -- | ---- |
| f(x)f(x) | 3 | -3 | -3 |
b) Determining the expression for f(x)f(x).
As derived above, f(x)=32xf(x) = \frac{3}{2}x.
Part 2:
Finding the coefficient of g(x)g(x) and the expression for g(x)g(x).
Since the line (Δ)(\Delta) passes through the origin, the function g(x)g(x) is of the form g(x)=bxg(x) = bx for some constant bb.
From the graph, we can see that the line (Δ)(\Delta) passes through the point (1.5,3)(1.5, -3). So, we have g(1.5)=3g(1.5) = -3. Thus, 1.5b=31.5b = -3, which means b=31.5=2b = \frac{-3}{1.5} = -2.
Therefore, g(x)=2xg(x) = -2x.
The coefficient of g(x)g(x) is 2-2.

3. Final Answer

Part 1:
a) The completed table is:
| xx | 2 | -2 | -3 |
| ------- | ---- | -- | ---- |
| f(x)f(x) | 3 | -3 | -3 |
b) The expression for f(x)f(x) is f(x)=32xf(x) = \frac{3}{2}x.
Part 2:
The coefficient of g(x)g(x) is 2-2. The expression for g(x)g(x) is g(x)=2xg(x) = -2x.

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