The problem has two parts. The first part deals with a linear function $f(x)$ represented by the line $(D)$. We are given a table with some $x$ values and corresponding $f(x)$ values, with some missing entries that we need to fill in. Then, we need to determine the expression for $f(x)$. The second part deals with another linear function $g(x)$ represented by the line $(\Delta)$. We need to find the coefficient of $g(x)$ and then determine the expression for $g(x)$.

AlgebraLinear FunctionsFunction AnalysisTable CompletionEquation of a LineCoefficients
2025/4/26

1. Problem Description

The problem has two parts. The first part deals with a linear function f(x)f(x) represented by the line (D)(D). We are given a table with some xx values and corresponding f(x)f(x) values, with some missing entries that we need to fill in. Then, we need to determine the expression for f(x)f(x). The second part deals with another linear function g(x)g(x) represented by the line (Δ)(\Delta). We need to find the coefficient of g(x)g(x) and then determine the expression for g(x)g(x).

2. Solution Steps

Part 1:
a) Completing the table for f(x)f(x).
We are given that f(2)=3f(2) = 3 and f(3)=3f(-3) = -3. Since f(x)f(x) is a linear function, we can write it as f(x)=axf(x) = ax for some constant aa.
Using the given information, f(2)=2a=3f(2) = 2a = 3, so a=32a = \frac{3}{2}. Thus, f(x)=32xf(x) = \frac{3}{2}x.
Now we can find the missing values in the table:
If x=2x = -2, then f(2)=32(2)=3f(-2) = \frac{3}{2}(-2) = -3.
We already have f(2)=3f(2)=3 and f(3)=3f(-3) = -3
The completed table is:
| xx | 2 | -2 | -3 |
| ------- | ---- | -- | ---- |
| f(x)f(x) | 3 | -3 | -3 |
b) Determining the expression for f(x)f(x).
As derived above, f(x)=32xf(x) = \frac{3}{2}x.
Part 2:
Finding the coefficient of g(x)g(x) and the expression for g(x)g(x).
Since the line (Δ)(\Delta) passes through the origin, the function g(x)g(x) is of the form g(x)=bxg(x) = bx for some constant bb.
From the graph, we can see that the line (Δ)(\Delta) passes through the point (1.5,3)(1.5, -3). So, we have g(1.5)=3g(1.5) = -3. Thus, 1.5b=31.5b = -3, which means b=31.5=2b = \frac{-3}{1.5} = -2.
Therefore, g(x)=2xg(x) = -2x.
The coefficient of g(x)g(x) is 2-2.

3. Final Answer

Part 1:
a) The completed table is:
| xx | 2 | -2 | -3 |
| ------- | ---- | -- | ---- |
| f(x)f(x) | 3 | -3 | -3 |
b) The expression for f(x)f(x) is f(x)=32xf(x) = \frac{3}{2}x.
Part 2:
The coefficient of g(x)g(x) is 2-2. The expression for g(x)g(x) is g(x)=2xg(x) = -2x.

Related problems in "Algebra"

The problem is to solve for $t$ in the equation $6.63 = 15[1 - e^{-t/10}]$.

Exponential EquationsLogarithmsEquation Solving
2025/6/21

We are given the equation $48x^3 = [2^{(2x)^3}]^2$ and we need to solve for $x$.

EquationsExponentsLogarithmsNumerical Solution
2025/6/20

We are asked to solve the quadratic equation $x^2 + x - 1 = 0$ for $x$.

Quadratic EquationsQuadratic FormulaRoots of Equations
2025/6/20

Solve the equation $\frac{x+1}{201} + \frac{x+2}{200} + \frac{x+3}{199} = -3$.

Linear EquationsEquation Solving
2025/6/20

The problem is to expand the given binomial expressions. The expressions are: 1. $(x + 1)(x + 3)$

Polynomial ExpansionBinomial ExpansionFOILDifference of Squares
2025/6/19

The problem is to remove the brackets and simplify the given expressions. I will solve question numb...

Algebraic ManipulationExpansionDifference of Squares
2025/6/19

We need to remove the brackets and collect like terms for the given expressions. I will solve proble...

Algebraic simplificationLinear expressionsCombining like termsDistribution
2025/6/19

The problem asks us to solve the equation $\lfloor 2x^3 - x^2 \rceil = 18x - 9$ for $x \in \mathbb{R...

EquationsCeiling FunctionReal NumbersCubic Equations
2025/6/19

The problem consists of 8 sub-problems. Each sub-problem contains an equation and a variable in pare...

Equation SolvingVariable IsolationFormula Manipulation
2025/6/19

The problem provides the equation of a parabola, $y = 3 - 2x - x^2$. We need to find the coordinates...

Quadratic EquationsParabolax-interceptTurning PointCoordinate Geometry
2025/6/19