The problem is to find the slope of the line passing through points $P(-10, 7)$ and $Q(2, 1)$. The given calculation for the slope $m$ is $m = \frac{1 - 7}{2 - (-10)}$.

GeometryCoordinate GeometrySlopeLinesPoints
2025/4/27

1. Problem Description

The problem is to find the slope of the line passing through points P(10,7)P(-10, 7) and Q(2,1)Q(2, 1). The given calculation for the slope mm is m=172(10)m = \frac{1 - 7}{2 - (-10)}.

2. Solution Steps

The formula for the slope mm of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
In this case, we have P(10,7)P(-10, 7) as (x1,y1)(x_1, y_1) and Q(2,1)Q(2, 1) as (x2,y2)(x_2, y_2).
Therefore, x1=10x_1 = -10, y1=7y_1 = 7, x2=2x_2 = 2, and y2=1y_2 = 1.
Plugging these values into the slope formula, we get:
m=172(10)m = \frac{1 - 7}{2 - (-10)}
m=62+10m = \frac{-6}{2 + 10}
m=612m = \frac{-6}{12}
m=12m = -\frac{1}{2}

3. Final Answer

The slope of the line passing through points P and Q is 12-\frac{1}{2}.

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