We are given the equation $14x + n = 132$ and we are asked to find the value of $n$ when $x = 6$.

AlgebraLinear EquationsSolving EquationsSubstitution
2025/4/27

1. Problem Description

We are given the equation 14x+n=13214x + n = 132 and we are asked to find the value of nn when x=6x = 6.

2. Solution Steps

First, substitute x=6x = 6 into the equation 14x+n=13214x + n = 132.
14(6)+n=13214(6) + n = 132
Now, calculate 14×614 \times 6.
14×6=8414 \times 6 = 84
So the equation becomes:
84+n=13284 + n = 132
Next, we want to isolate nn. To do this, subtract 8484 from both sides of the equation.
84+n84=1328484 + n - 84 = 132 - 84
n=13284n = 132 - 84
Finally, calculate 13284132 - 84.
13284=48132 - 84 = 48
Therefore, n=48n = 48.

3. Final Answer

n=48n = 48

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