The image presents several problems. We will solve the first problem: "Determine the point of intersection of the following lines: 1) $x - 2y - 4 = 0$; $2x + 3y - 1 = 0$".

1. Problem Description

The image presents several problems. We will solve the first problem: "Determine the point of intersection of the following lines: 1) $x - 2y - 4 = 0$; $2x + 3y - 1 = 0$".

2. Solution Steps

We have the following system of equations:

$x - 2y - 4 = 0$ (1)

$2x + 3y - 1 = 0$ (2)

From equation (1), we can express $x$ in terms of $y$:

$x = 2y + 4$ (3)

Substitute (3) into equation (2):

$2(2y + 4) + 3y - 1 = 0$

$4y + 8 + 3y - 1 = 0$

$7y + 7 = 0$

$7y = -7$

$y = -1$

Now, substitute $y = -1$ into equation (3):

$x = 2(-1) + 4$

$x = -2 + 4$

$x = 2$

Therefore, the point of intersection is $(2, -1)$.

3. Final Answer

The point of intersection is $(2, -1)$.