The problem appears to be about solving for $y$ in terms of $x$ and constants $a$ and $b$. The given equation is $y = \frac{a}{b}(x-3)^2$.

AlgebraEquationsVariablesQuadraticFunctions
2025/4/28

1. Problem Description

The problem appears to be about solving for yy in terms of xx and constants aa and bb. The given equation is y=ab(x3)2y = \frac{a}{b}(x-3)^2.

2. Solution Steps

The equation is already solved for yy in terms of xx. The equation is y=ab(x3)2y = \frac{a}{b}(x-3)^2. There are no further steps to be taken to solve for yy in this case, as it is already isolated.

3. Final Answer

y=ab(x3)2y = \frac{a}{b}(x-3)^2

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