Paula calculated that a large oak tree can transpire $4.15 \times 10^5$ milliliters of water per day. We need to find the most appropriate unit for Paula to use instead of milliliters per day.

1. Problem Description

Paula calculated that a large oak tree can transpire $4.15 \times 10^5$ milliliters of water per day. We need to find the most appropriate unit for Paula to use instead of milliliters per day.

2. Solution Steps

We are given the transpiration rate as $4.15 \times 10^5$ milliliters per day. We want to find a more appropriate unit.

First, let's convert milliliters to liters. We know that 1 liter = 1000 milliliters.

Therefore, we can convert milliliters to liters by dividing by 1000:

$4.15 \times 10^5 \text{ milliliters/day} = \frac{4.15 \times 10^5}{1000} \text{ liters/day} = 4.15 \times 10^2 \text{ liters/day} = 415 \text{ liters/day}$.

Now, let's convert days to hours. We know that 1 day = 24 hours.

Therefore, we can convert liters per day to liters per hour by dividing by 24:

$415 \text{ liters/day} = \frac{415}{24} \text{ liters/hour} \approx 17.29 \text{ liters/hour}$.

The options given are:

- milliliters per hour

- liters per hour

- liters per second

- liters per year

Since $4.15 \times 10^5$ milliliters per day is equal to 415 liters per day, and we calculated it to be about 17.29 liters per hour, "liters per hour" seems to be the most appropriate unit. Milliliters per hour would be a very small number, and liters per second would also be quite small. Liters per year would be a very large number.

3. Final Answer

liters per hour